The disc of mass M with uniform surface mass density σ is shown in the figure. The center of mass of…

The disc of mass $M$ with uniform surface mass density $\sigma$ is shown in the figure. The center of mass of the quarter disc (the shaded area) is at the position $\left(\frac{xa}{3\pi }, \frac{xa}{3\pi }\right)$ where $x$ is _______ . (Round off to the Nearest Integer) [$a$ is an area as shown in the figure]