The direction cosines of the vector \(\mathbf{a}=-2 \hat{\mathbf{i}}+\hat{\mathbf{j}}-5 \hat{\mathbf{k}}\) are

The direction cosines of the vector \(\mathbf{a}=-2 \hat{\mathbf{i}}+\hat{\mathbf{j}}-5 \hat{\mathbf{k}}\) are
  1. \(\frac{-2}{\sqrt{8}}, \frac{1}{\sqrt{8}}, \frac{-5}{\sqrt{8}}\)
  2. \(\frac{-2}{\sqrt{30}}, \frac{1}{\sqrt{30}}, \frac{-5}{\sqrt{30}}\)
  3. \(\frac{2}{\sqrt{8}}, \frac{-1}{\sqrt{8}}, \frac{5}{\sqrt{8}}\)
  4. \(\frac{-2}{\sqrt{30}}, \frac{-1}{\sqrt{30}}, \frac{-5}{\sqrt{30}}\)

Solution

The direction cosines of vector \(\mathbf{a}=-2 \hat{\mathbf{i}}+\hat{\mathbf{j}}-5 \hat{\mathbf{k}}\) are \(-\frac{2}{|\mathbf{a}|}, \frac{1}{|\mathbf{a}|}, \frac{-5}{|\mathbf{a}|}\) \(\because \quad|\mathbf{a}|=\sqrt{4+1+25}=\sqrt{30}\) \(\therefore\) Required direction cosines are \(-\frac{2}{\sqrt{30}}, \frac{1}{\sqrt{30}},-\frac{5}{\sqrt{30}}\) Hence, option (b) is correct.

Asked in: AP EAMCET 2020 (21 Sep Shift 1)

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