We know that
$\cos ^{2} \alpha+\cos ^{2} \beta+\cos ^{2} \gamma=1$ and given $\alpha=\beta=\gamma$
$\therefore 3 \cos ^{2} \alpha=1 \Rightarrow \cos ^{2} \alpha=\frac{1}{3} \Rightarrow \cos \alpha=\cos \beta=\cos \gamma=\frac{1}{\sqrt{3}}$
Note: Angles are acute. So positive sign of $\frac{1}{\sqrt{3}}$ is considered.