The dimensions of coefficient of self inductance are
- $\left[\mathrm{ML}^{2} \mathrm{~T}^{-2} \mathrm{~A}^{-2}\right]$
- $\left[\mathrm{ML}^{2} \mathrm{~T}^{-2} \mathrm{~A}^{-1}\right]$
- $\left[\mathrm{MLT}^{-2} \mathrm{~A}^{-2}\right]$
- $\left[\mathrm{MLT}^{-2} \mathrm{~A}^{-1}\right]$
Solution
$[\mathrm{L}]=\frac{\left[\mathrm{ML}^{2} \mathrm{~T}^{-2}\right]}{[\mathrm{A}]^{2}}=\left[\mathrm{ML}^{2} \mathrm{~T}^{-2} \mathrm{~A}^{-2}\right]$ undefined
Asked in: JEE Mains - Units and Dimensions - Test 1