The dimensions of $\left(\mu_0 \varepsilon_0\right)^{-1 / 2}$ are
The dimensions of $\left(\mu_0 \varepsilon_0\right)^{-1 / 2}$ are
- $\left[\mathrm{L}^{1 / 2} \mathrm{~T}^{-1 / 2}\right]$
- $\left[\mathrm{L}^{-1} \mathrm{~T}\right]$
- $\left[\mathrm{LT}^{-1}\right]$
- $\left[\mathrm{L}^{1 / 2} \mathrm{~T}^{1 / 2}\right]$
Solution
$\left(\mu_0 \varepsilon_0\right)^{-1 / 2}$ is velocity of light
Hence $\quad c=\frac{1}{\sqrt{\mu_0 \varepsilon_0}}=\left[\mathrm{LT}^{-1}\right]$
Asked in: NEET 2012 (Mains)
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