The diffusion coefficient of an ideal gas is proportional to its mean free path and mean speed. The absolute temperature of an ideal gas is increased 4 times and its pressure 2 times. As a result, the diffusion coefficient of this gas increases x times. The value of x is:

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Aicharya · Accepted Answer

Rate of diffusion &#8733; &#955; &#215; U Avg &#8733; 1 2 &#960;&#963; 2 N * &#215; U Avg &#8733; 1 2 &#960;&#963; 2 N * &#8733; &#160; U Avg &#160; kT 2 &#960;&#963; 2 P Rate of diffusion &#8733; T 3 2 P r final r initial = 4 3 2 2 r final r initial = 4

The diffusion coefficient of an ideal gas is proportional to its mean free path and mean speed. The absolute…

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