The differential equation $\frac{d y}{d x}=\frac{1}{a x+b y+c}$, where $a, b, c$ are all non-zero real numbers, is

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Aicharya · Accepted Answer

Given differential equation, $\begin{aligned} & \frac{d y}{d x}=\frac{1}{a x+b y+c} \ & \frac{d y}{d x}=a x+b y+c \ & \frac{d x}{d y}-a x=b y+c \end{aligned}$ Hence, this equation is a linear differential equation in $x$.

The differential equation $\frac{d y}{d x}=\frac{1}{a x+b y+c}$, where $a, b, c$ are all non-zero real…

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