The differential equation representing the family of curves $y^2=2 \mathrm{c}(x+\sqrt{\mathrm{c}})$, where…
The differential equation representing the family of curves $y^2=2 \mathrm{c}(x+\sqrt{\mathrm{c}})$, where $\mathrm{c}$ is a positive parameter, is of
order 1, degree 4
order 2, degree 3
order 2, degree 4
order 1, degree 3
Solution
$y^2=2 \mathrm{c}(x+\sqrt{\mathrm{c}})... (i)$
Differentiating w.r.t. $x$, we get
$2 y \frac{\mathrm{d} y}{\mathrm{~d} x}=2 \mathrm{c}... (ii)$
Substituting (ii) in (i), we get
$\begin{aligned}
& y^2=2 y \frac{\mathrm{d} y}{\mathrm{~d} x}\left(x+\sqrt{y \frac{\mathrm{d} y}{\mathrm{~d} x}}\right) \\
& \Rightarrow y=2 x \frac{\mathrm{d} y}{\mathrm{~d} x}+2 \frac{\mathrm{d} y}{\mathrm{~d} x} \sqrt{y \frac{\mathrm{d} y}{\mathrm{~d} x}} \\
& \Rightarrow\left(y-2 x \frac{\mathrm{d} y}{\mathrm{~d} x}\right)^2=4 y\left(\frac{\mathrm{d} y}{\mathrm{~d} x}\right)^3
\end{aligned}$
This is a differential equation of order 1 and degree 3 .