The differential equation of an ellipse whose major axis is twice its minor axis, is
The differential equation of an ellipse whose major axis is twice its minor axis, is
$x+4 y \frac{d y}{d x}=0$
$x-4 y \frac{d y}{d x}=0$
$x+2 y \frac{d y}{d x}=0$
None of these
Solution
For the given ellipse, we have $\mathrm{a}=2 \mathrm{~b}$
$\therefore \therefore \frac{\mathrm{x}^2}{4 \mathrm{~b}^2}+\frac{\mathrm{y}^2}{\mathrm{~b}^2}=1 \Rightarrow \mathrm{x}^2+4 \mathrm{y}^2=4 \mathrm{~b}^2$
Differentiating both sides w.r.t., we get
$2 x+8 y \frac{d y}{d x}=0 \Rightarrow x+4 y \frac{d y}{d x}=0$