The differential equation corresponding to the family of circles given by $(x-a)^2+(y-b)^2=4$, where $a$ and…

The differential equation corresponding to the family of circles given by $(x-a)^2+(y-b)^2=4$, where $a$ and $b$ are parameters, is
  1. $4 \frac{d^2 y}{d x^2}+9 y=0$
  2. $4\left(\frac{d^2 y}{d x^2}\right)^2=\left[1+\left(\frac{d y}{d x}\right)^2\right]^3$
  3. $4 \frac{d^2 y}{d x^2}+\left(\frac{d y}{d x}\right)^2=6 y$
  4. $4\left(\frac{d^2 y}{d x^2}\right)^2+\left[1+\left(\frac{d y}{d x}\right)^2\right]^2=0$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (24 Apr Shift 1)

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