The difference in the oxidation numbers of the two types of sulphur atoms in $\mathrm{Na}_2 \mathrm{~S}_4…

The difference in the oxidation numbers of the two types of sulphur atoms in $\mathrm{Na}_2 \mathrm{~S}_4 \mathrm{O}_6$ is

Solution

$ \mathrm{Na}_2 \mathrm{~S}_4 \mathrm{O}_6 \text { is a salt of } \mathrm{H}_2 \mathrm{~S}_4 \mathrm{O}_6 \text { which has the following structure } $
$ \Rightarrow \text { Difference in oxidation number of two types of sulphur }=5 $

Asked in: JEE Advanced 2011 (Paper 1)

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