The diameter of a spherical bob, when measured with vernier callipers yielded the following values: $3.33…
The diameter of a spherical bob, when measured with vernier callipers yielded the following values: $3.33 \mathrm{~cm}$, $3.32 \mathrm{~cm}, 3.34 \mathrm{~cm}, 3.33 \mathrm{~cm}$ and $3.32 \mathrm{~cm}$.
The mean diameter to appropriate significant figures is:
$3.33 \mathrm{~cm}$
$3.32 \mathrm{~cm}$
$3.328 \mathrm{~cm}$
$3.3 \mathrm{~cm}$
Solution
$\begin{aligned} \text { Mean diameter } & =\frac{[3.33 \mathrm{~cm}+3.32 \mathrm{~cm}+3.34 \mathrm{~cm}+3.33 \mathrm{~cm}+3.32 \mathrm{~cm}]}{5} \\ & =3.328 \mathrm{~cm}\end{aligned}$
After rounding off to 2 decimal places.
Final mean diameter $=3.33 \mathrm{~cm}$