The diagonals of a quadrilateral $PQRS$ are perpendicular and measure $16$ cm and $9$ cm. Find the area of…
The diagonals of a quadrilateral $PQRS$ are perpendicular and measure $16$ cm and $9$ cm. Find the area of the quadrilateral.
- $72 \text{ cm}^{2}$
- $144 \text{ cm}^{2}$
- $50 \text{ cm}^{2}$
- $36 \text{ cm}^{2}$
Solution
When diagonals of a quadrilateral are perpendicular, area $= \dfrac{1}{2} d_{1} d_{2} = \dfrac{1}{2}\times 16 \times 9 = 72 \text{ cm}^{2}$.
Asked in: IMO
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