The diagonals of a quadrilateral are perpendicular to each other. If $d_{1} = 2 d_{2}$ and the area is $144…
The diagonals of a quadrilateral are perpendicular to each other. If $d_{1} = 2 d_{2}$ and the area is $144 \text{ cm}^{2}$, find $d_{1}$.
- $12$ cm
- $24$ cm
- $18$ cm
- $36$ cm
Solution
Area $= \dfrac{1}{2} d_{1} d_{2} = \dfrac{1}{2}(2 d_{2}) d_{2} = d_{2}^{2} = 144 \Rightarrow d_{2} = 12$. Hence $d_{1} = 24$ cm.
Asked in: IMO
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