The diagonals of a quadrilateral are perpendicular to each other. If $d_{1} = 2 d_{2}$ and the area is $144…

The diagonals of a quadrilateral are perpendicular to each other. If $d_{1} = 2 d_{2}$ and the area is $144 \text{ cm}^{2}$, find $d_{1}$.
  1. $12$ cm
  2. $24$ cm
  3. $18$ cm
  4. $36$ cm

Solution

Area $= \dfrac{1}{2} d_{1} d_{2} = \dfrac{1}{2}(2 d_{2}) d_{2} = d_{2}^{2} = 144 \Rightarrow d_{2} = 12$. Hence $d_{1} = 24$ cm.

Asked in: IMO

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