The diagonal of a square is $10\sqrt{2}$ cm. Find its area.
The diagonal of a square is $10\sqrt{2}$ cm. Find its area.
- $50 \text{ cm}^{2}$
- $100 \text{ cm}^{2}$
- $200 \text{ cm}^{2}$
- $25 \text{ cm}^{2}$
Solution
If diagonal $d = a\sqrt{2}$, then $a = 10$ cm. Area $= a^{2} = 100 \text{ cm}^{2}$. Equivalent shortcut: area $= \dfrac{d^{2}}{2} = \dfrac{200}{2} = 100$.
Asked in: IMO
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