The descending order of acidity for the following carboxylic acid is-
(A) ${CH}_{3} COOH$
(B) $F_{3} C - COOH$
(C) ${ClCH}_{2} - COOH$
(D) ${FCH}_{2} - COOH$
(E) ${BrCH}_{2} - COOH$
Choose the correct answer from the options given below:

Question

The descending order of acidity for the following carboxylic acid is-
(A)

{CH}_{3} COOH

(B)

F_{3} C - COOH

(C)

{ClCH}_{2} - COOH

(D)

{FCH}_{2} - COOH

(E)

{BrCH}_{2} - COOH

Choose the correct answer from the options given below:

Aicharya · Accepted Answer

The correct order of acidic strength of the given carboxylic acids will be decided by the stability of their conjugate bases. The $+ I$ effect of ${CH}_{3}$ group destabilises the carboxylate anion. But the $- I$ effect of halogen substituted methyl group stabilises the carboxylate anion. Higher the $- I$ effect of the halogen substituted methyl group, higher the acidic strength of the corresponding acid.
$∴$ Correct order of acidic strength is
$F_{3} C - \underset{(B)}{COOH} > {FCH}_{2} - \underset{(D)}{COOH} > \underset{(C)}{{CICH}_{2} - COOH} > \underset{(E)}{{BrCH}_{2} - COOH} > \underset{(A)}{{CH}_{3} - COOH}$

The descending order of acidity for the following carboxylic acid is- (A) CH 3 COOH (B) F 3 C - COOH (C)…

Solution