The depression in freezing point of solution of molality $0.01 \mathrm{~mol} \mathrm{~kg}^{-1}$ is highest…

The depression in freezing point of solution of molality $0.01 \mathrm{~mol} \mathrm{~kg}^{-1}$ is highest with respect to which of the solvent? (Whose $K_f$ is given in brackets)
  1. Water (1.86)
  2. Benzene (5.12)
  3. Carbon tetrachloride (31.8)
  4. Cyclohexane (20.0)

Solution

Given, molality of solution $=0.01 \mathrm{~mol} \mathrm{~kg}^{-1}$ We know that, $\Delta T_f=i K_f m$...(i) (where, symbols have their usual meaning) The van't Hoff factor for all given solvent is 1 as they does not ionise. Therefore, For, Eq (i) $\Delta T_f \propto K_f$ Therefore, the depression in freezing point of given solution is highest for carbon tetrachloride because its $K_f$ value is highest.

Asked in: AP EAMCET 2022 (08 Jul Shift 2)

Practice more Solutions questions on Aicharya