The density of oxygen gas at $5 \mathrm{~atm}$ and $127^{\circ} \mathrm{C}$ will be

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Aicharya · Accepted Answer

Density of a gas, $\begin{aligned} d & =\frac{p M}{R T} \ {[\because \quad p} & =\text { pressure }=5 \mathrm{~atm} \ M & =\text { molar mass of } \mathrm{O}_2 \text { gas }=32 \mathrm{~g} \mathrm{~mol}^{-1} \ R & =0.082 \mathrm{~L} \text { atm } \mathrm{mol}^{-1} \mathrm{~K}^{-1} \ T & =400 \mathrm{~K}] \ & =\frac{5 \times 32}{0.082 \times(273+127)} \ & =4.878 \simeq 4.88 \mathrm{gL}^{-1} \end{aligned}$

The density of oxygen gas at \(5 \mathrm{~atm}\) and \(127^{\circ} \mathrm{C}\) will be

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