The densities of graphite and diamond at $298 \mathrm{~K}$ are 2.25 and $3.31 \mathrm{gcm}^{-3}$, respectively. If the standard free energy difference $\left(\Delta \mathrm{G}^{\circ}\right)$ is equal to $1895 \mathrm{~J} \mathrm{~mol}^{-1}$, the pressure at which graphite will be transformed into…

Question

The densities of graphite and diamond at $298 \mathrm{~K}$ are 2.25 and $3.31 \mathrm{gcm}^{-3}$, respectively. If the standard free energy difference $\left(\Delta \mathrm{G}^{\circ}\right)$ is equal to $1895 \mathrm{~J} \mathrm{~mol}^{-1}$, the pressure at which graphite will be transformed into diamond at $298 \mathrm{~K}$ is:

Aicharya · Accepted Answer

$\Delta \mathrm{G}=-\mathrm{P} \Delta \mathrm{V}$ $\begin{aligned} & 1895=P\left[\left(\frac{12}{2.25}-\frac{12}{3.31}ight) 	imes 10^{-6} \mathrm{~m}^3ight] \ & P=\frac{1895 	imes 10^6}{1.71}=1108.187 	imes 10^6 \mathrm{Bar} \ & =1108.1871 	imes 10^{11} \mathrm{~Pa} \end{aligned}$

The densities of graphite and diamond at $298 \mathrm{~K}$ are 2.25 and $3.31 \mathrm{gcm}^{-3}$,…

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