The degree of the differential equation whose solution is $y^2=8 a(x+a)$, is

The degree of the differential equation whose solution is $y^2=8 a(x+a)$, is
  1. 2
  2. 1
  3. 4
  4. 3

Solution

We have $y^2=8 a x+8 a^2$ Differentiating w.r.t. $\mathrm{x}$, we get $2 y \frac{d y}{d x}=8 a \quad \Rightarrow \quad a=\left(\frac{y}{4}\right) \frac{d y}{d x}$ Substituting value of ' $a$ ' in eq. (1), we get $\begin{aligned} & y^2=8\left(\frac{y}{4}\right) \frac{d y}{d x}(x)+8\left[\left(\frac{y}{4}\right)\left(\frac{d y}{d x}\right)\right]^2=2 x y \frac{d y}{d x}+\left(\frac{y^2}{2}\right)\left(\frac{d y}{d x}\right)^2 \\ & \therefore 2 y^2=4 x y\left(\frac{d y}{d x}\right)+y^2\left(\frac{d y}{d x}\right)^2 \end{aligned}$ Hence order $=1$, degree $=2$

Asked in: MHT CET 2021 (22 Sep Shift 2)

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