The deflection in moving coil galvanometer falls from 25 divisions to 5 division when a shunt of 24 Ω is…

Let $x$ represents the current per division though the galvanometer.

After applying shunt

Now, if $G$ is the galvanometer resistance, from the above figure, it can be written that

$$\begin{gathered} 5x\times G=20x\times 24 \\ \Rightarrow G=4\times 24 \\ \Rightarrow G=96 \mathrm{\Omega } \end{gathered}$$