The decreasing values of bond angles from $\mathrm{NH}_3\left(106^{\circ}\right)$ to…

The decreasing values of bond angles from $\mathrm{NH}_3\left(106^{\circ}\right)$ to $\mathrm{SbH}_3\left(101^{\circ}\right)$ down group-15 of the periodic table is due to
  1. increasing bp-bp repulsion
  2. increasing p-orbital character in $\mathrm{sp}^3$
  3. decreasing Ip-bp repulsion
  4. decreasing electronegativity

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Asked in: JEE Main 2006

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