The decreasing order of reactivity of following alcohols with halo acid is (I) $\mathrm{CH}_3 \mathrm{OH}$…

The decreasing order of reactivity of following alcohols with halo acid is (I) $\mathrm{CH}_3 \mathrm{OH}$ (II) $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH}$ (III)
(IV)
  1. (IV) $\gt$ (III) $\gt$ (II) $\gt$ (I)
  2. (I) $\gt$ (II) $\gt$ (III) $\gt$ (IV)
  3. (II) $\gt$ (I) $\gt$ (IV) $\gt$ (III)
  4. $\quad(IV) $>$ (II) $>$ (III) $>$ (I)

Solution

The order of reactivity of alcohols with halo acid is $3^{\circ}\gt2^{\circ}\gt1^{\circ}$.

Asked in: MHT CET 2024 (09 May Shift 1)

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