Chemistry › Thermodynamics (C) › Laws of Thermochemistry and Enthalpy Change
The decreasing order of bond dissociation energies of $\mathrm{C}-\mathrm{C}, \mathrm{C}-\mathrm{H}$ and…
The decreasing order of bond dissociation energies of $\mathrm{C}-\mathrm{C}, \mathrm{C}-\mathrm{H}$ and $\mathrm{H}-\mathrm{H}$ bonds is
$\mathrm{H}-\mathrm{H}>-\mathrm{C}-\mathrm{H}>-\mathrm{C}-\mathrm{C}-$ $-\mathrm{C}-\mathrm{C}->\mathrm{C}-\mathrm{H}>\mathrm{H}-\mathrm{H}$ $-\mathrm{C}-\mathrm{H}>-\mathrm{C}-\mathrm{C}->\mathrm{H}-\mathrm{H}$ $-\mathrm{C}-\mathrm{C}->\mathrm{H}-\mathrm{H}>-\mathrm{C}-\mathrm{H}$
Solution
The decreasing order of bond dissociation energies of $\mathrm{C}-\mathrm{C}, \mathrm{C}-\mathrm{H}$ and $\mathrm{H}-\mathrm{H}$ bonds is as:
$\mathrm{H}-\mathrm{H}>-\mathrm{C}-\mathrm{H}>-\mathrm{C}-\mathrm{C}-$
Asked in: AP EAMCET 2007
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