The decreasing order of boiling points of the following alkanes is: (a) Heptane (b) butane (c)…
The decreasing order of boiling points of the following alkanes is:
(a) Heptane
(b) butane
(c) 2-methylbutane
(d) 2-methylpropane
(e) hexane
Choose the correct answer from the options given below:
(a) $>$ (c) $>$ (e) $>$ (d) $>$ (b)
(c) $>$ (d) $>$ (a) $>$ (e) $>$ (b)
(a) $>$ (e) $>$ (b) $>$ (c) $>$ (d)
(a) $>$ (e) $>$ (c) $>$ (b) $>$ (d)
Solution
With increase in molecular mass, van Der Waal force increases and hence boiling point also increases.
$\therefore$ BP : Heptane \(>\) Hexane \(>\) 2- Methyl Butane \(>\) Butane \(>\) 2- methly propane with the increase in branching, surface area decreases of molecules of same molecular mass which results in decrease in boiling point.