The decomposition of a substance follows first order kinetics. Its concentration is reduced to $1 / 8$ th of its initial value in 24 minutes. The rate constant of the decomposition process in $\min ^{-1}$ is

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Aicharya · Accepted Answer

$\mathrm{k}=\frac{2.303}{\mathrm{t}} \log \frac{\mathrm{a}}{\mathrm{a}-\mathrm{x}}=\frac{2.303}{24} \log \frac{1}{\frac{1}{8}}=\frac{2.303}{24} \log 8$ $=0.087 \mathrm{~min}^{-1}$ .

The decomposition of a substance follows first order kinetics. Its concentration is reduced to $1 / 8$ th of…

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