The de' Broglie wavelength of a particle is $1000 \mathrm{~nm}$. What is its momentum? $\left(\mathrm{h}=6.6…

The de' Broglie wavelength of a particle is $1000 \mathrm{~nm}$. What is its momentum? $\left(\mathrm{h}=6.6 \times 10^{-34} \mathrm{~J} \mathrm{~s}\right)$
  1. $6.6 \times 10^{-25} \mathrm{~J} \mathrm{~s} \mathrm{~m}^{-1}$
  2. $6.6 \times 10^{-25} \mathrm{~J} \mathrm{~s} \mathrm{~m}$
  3. $6.6 \times 10^{-28} \mathrm{~J} \mathrm{~s} \mathrm{~m}^{-1}$
  4. $6.6 \times 10^{-26} \mathrm{~J} \mathrm{~s} \mathrm{~m}$

Solution

$\lambda=1000 \mathrm{~nm}=1000 \times 10^{-9} \mathrm{~m}=1.0 \times 10^{-6} \mathrm{~m}$ $\Rightarrow P=\frac{h}{\lambda}=\frac{6.626 \times 10^{-34}}{1.0 \times 10^{-6}}=6.626 \times 10^{-28} \mathrm{~J} \mathrm{~s} \mathrm{~m}^{-1}$

Asked in: AP EAMCET 2023 (18 May Shift 1)

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