The de-Broglie wavelength associated with an electron and a proton were calculated by accelerating them…

The de-Broglie wavelength associated with an electron and a proton were calculated by accelerating them through same potential of 100 V. What should nearly be the ratio of their wavelengths ?  mp=1.00727 u,me=0.00055 u
  1. 1860 : 1
  2. 18602 : 1
  3. 41.4 : 1
  4. 43 : 1

Solution

λ=hmv=h2mK=h2mqV

λ1λ2=m2 m1

λeλp=mpme=1831.4=42.79

Asked in: JEE Main 2021 (16 Mar Shift 2)

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