The d- electronic configuration of an octahedral Co(II) complex having magnetic moment of 3.95 BM is:
- $\mathrm{t}_{2 \mathrm{~g}}{ }^3 \mathrm{e}_{\mathrm{g}}{ }^0$
- $\mathrm{t}_{2 \mathrm{~g}}{ }^6 \mathrm{e}_{\mathrm{g}}{ }^1$
- $\mathrm{t}_{2 \mathrm{~g}}{ }^5 \mathrm{e}_{\mathrm{g}}{ }^2$
- $\mathrm{e}^4 \mathrm{t}_2{ }^3$
Solution
Hence number of unpaired electron $=3$
$\mathrm{Co}^{2+} \Rightarrow 3 d^7=\mathrm{t}_{2 \mathrm{~g}}^5 \mathrm{e}_{\mathrm{g}}^2$
Asked in: JEE Main 2025 (23 Jan Shift 1)