The current voltage relation of diode is given by $I = (e^{1000\frac{V}{T}} - 1)$ mA, where the applied…

The current voltage relation of diode is given by $I = (e^{1000\frac{V}{T}} - 1)$ mA, where the applied voltage $V$ is in volts and the temperature $T$ is in degree Kelvin. If a student makes an error measuring $\pm 0.01$ V while measuring the current of 5 mA at 300 K, what will be the error in the value of current in mA ?
  1. 0.2 mA
  2. 0.02 mA
  3. 0.5 mA
  4. 0.05 mA

Solution

$I = (e^{1000V/T} - 1) \, \text{mA}$ When $I = 5 \, \text{mA}$, $e^{1000V/T} = 6 \, \text{mA}$ Also, $dI = (e^{1000V/T}) \times $\frac{1000}{T}$ \cdot dV$ $= (6 \, \text{mA}) \times \frac{1000}{300}\times 0.01$ $= 0.2 \, \text{mA}$

Asked in: JEE Main 2014 (06 Apr)

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