The current through $1 \Omega$ resistance in the following circuit is

Question

Aicharya · Accepted Answer

For a balanced Wheatstone bridge ratio of resistors is $\frac{R_{P Q}}{R_{P S}}=\frac{R_{Q R}}{R_{S R}}$ $\begin{aligned} & 	herefore i\left(R_{P Q}+R_{Q R}ight)=(I-i)\left(R_{P S}+R_{S R}ight) \ & \Rightarrow(5+1) i=(2.1-i)(12.5+2.5) \ & \Rightarrow \frac{2.1-i}{i}=\frac{6}{15} \ & \Rightarrow \frac{2.1}{i}=\frac{7}{5} \ & \Rightarrow i=1.5 \mathrm{~A}\end{aligned}$

The current through $1 \Omega$ resistance in the following circuit is

Solution