The current in an inductor is given by $\mathrm{I}=(3 \mathrm{t}+8)$ where $\mathrm{t}$ is in second. The…

The current in an inductor is given by $\mathrm{I}=(3 \mathrm{t}+8)$ where $\mathrm{t}$ is in second. The magnitude of induced emf produced in the inductor is $12 \mathrm{mV}$. The self-inductance of the inductor _____ $\mathrm{mH}$.

Solution

$\begin{aligned} & \mathrm{I}=3 \mathrm{t}+8 \\ & \varepsilon=12 \mathrm{mV} \\ & |\varepsilon|=\mathrm{L}\left|\frac{\mathrm{dI}}{\mathrm{dt}}\right| \\ & 12=\mathrm{L} \times 3 \\ & \mathrm{~L}=4 \mathrm{mH}\end{aligned}$

Asked in: JEE Main 2024 (05 Apr Shift 2)

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