The current flowing through the $1 \Omega$ resistor is $\frac{n}{10}$ A. The value of $n$ is _________

The current flowing through the $1 \Omega$ resistor is $\frac{n}{10}$ A. The value of $n$ is _________

Solution


$\begin{aligned} & \frac{y-5}{2}+\frac{y-0}{2}+\frac{y-x+10}{1}=0 \\ & y-5+y+2 y-2 x+20=0 \\ & 4 y-2 x+15=0 \quad \ldots .(\text { (i) } \\ & \frac{x-5}{4}+\frac{x-0}{4}+\frac{x-10-y}{1}=0 \\ & x-5+x+4 x-40-4 y=0 \\ & 6 x-4 y-45=0 \quad . .(i) \\ & \frac{-2 x+4 y+15=0 . .(i i)}{4 x-30=0} \\ & x=\frac{15}{2} \& 4 y-15+15=0 \\ & y=0 \\ & i=\frac{y-x+10}{1} \\ & i=\frac{0-7.5+10}{1} \\ & i=2.5 A=\frac{n}{10} A \\ & n=25\end{aligned}$

Asked in: JEE Main 2024 (09 Apr Shift 1)

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