The current flowing in a coil is 3 A and the power consumed is 108 W . If the a.c. source is of $120…

The current flowing in a coil is 3 A and the power consumed is 108 W . If the a.c. source is of $120 \mathrm{~V}, 50 \mathrm{~Hz}$, the resistance in the circuit is
  1. $24 \Omega$
  2. $36 \Omega$
  3. $12 \Omega$
  4. $6 \Omega$

Solution

$\begin{array}{ll} & \mathrm{P}=\mathrm{I}_{\mathrm{rms}}{ }^2 \mathrm{R} \\ \therefore \quad & 108=(3)^2 \mathrm{R} \\ & \mathrm{R}=12 \Omega\end{array}$

Asked in: MHT CET 2024 (02 May Shift 2)

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