The current density in a cylindrical wire of radius r = 4 . 0   mm is 1 . 0 × 10 6   A 2   m 2 . The current through the outer portion of the wire between radial distances r 2 and r is x π   A ; where x is

Question

The current density in a cylindrical wire of radius r = 4 . 0 &#160; mm is 1 . 0 &#215; 10 6 &#160; A 2 &#160; m 2 . The current through the outer portion of the wire between radial distances r 2 and r is x &#960; &#160; A ; where x is

Aicharya · Accepted Answer

Current = J &#215; Area = J &#215; &#960; R 2 - R 2 2 = J &#960; 3 R 2 4 = 10 6 &#215; &#960; &#215; 3 &#215; 4 &#215; 10 - 3 4 2 &#8658; &#960; &#215; 3 &#215; 16 4 = 12 &#960; &#160; A Hence, the value of x = 12 .

The current density in a cylindrical wire of radius r = 4 . 0   mm is 1 . 0 × 10 6   A 2…

Solution

The current density in a cylindrical wire of radius r = 4 . 0 &#160; mm is 1 . 0 &#215; 10 6 &#160; A 2…

Solution

The current density in a cylindrical wire of radius r = 4 . 0 mm is 1 . 0 × 10 6 A 2…