The current and emf through an inductance differ by phase by
The current and emf through an inductance differ by phase by
$\frac{\pi}{4}$
$\frac{\pi}{2}$
$\frac{\pi}{3}$
$\pi$
Solution
We know that, in pure inductive circuit,
Alternating voltage, $V=V_0 \sin \omega t$
and alternating current, $I=I_0 \sin (\omega t-\pi / 2)$
From the above two equations, it can be seen that
alternative current and EMF differ by $\frac{\pi}{2}$ phase.