The current amplification factor and the collector current in a CE transistor circuit are 100 and $2.2…
The current amplification factor and the collector current in a CE transistor circuit are 100 and $2.2 \mathrm{~mA}$ respectively. Then the base current is
$0.22 \mu \mathrm{A}$
$22 \mu \mathrm{A}$
$220 \mu \mathrm{A}$
$2.2 \mu \mathrm{A}$
Solution
Current amplification favor, $\beta=100$
Collector around, $I_c=2.2 \mathrm{~mA}$
Base current, $\mathrm{I}_{\mathrm{B}}$
Using the relation,
$\begin{aligned} & \beta=\frac{I_C}{I_B} \\ & I_B=\frac{I_C}{\beta}=\frac{2.2 \times 10^{-3}}{100}=2.2 \times 10^{-5} \\ & I_\beta=22 \mu \mathrm{A}\end{aligned}$