The cost of running a bus from $A$ to $B$, is $₹\left(a v+\frac{b}{v}\right)$, where $v \mathrm{~km} /…

The cost of running a bus from $A$ to $B$, is $₹\left(a v+\frac{b}{v}\right)$, where $v \mathrm{~km} / \mathrm{h}$ is the average speed of the bus. When the bus travels at $30 \mathrm{~km} / \mathrm{h}$, the cost comes out to be $₹ 75$ while at $40 \mathrm{~km} / \mathrm{h}$, it is $₹ 65$. Then the most economical speed (in $\mathrm{km} / \mathrm{h}$ ) of the bus is :
  1. 45
  2. 50
  3. 60
  4. 40

Solution

Let $\operatorname{cost} \mathrm{C}=a v+\frac{b}{v}$ According to given question, $ \begin{aligned} & 30 a+\frac{b}{30}=75 \\ & 40 a+\frac{b}{40}=65 \end{aligned} $ On solving (i) and (ii), we get $a=\frac{1}{2}$ and $b=1800$ Now, $C=a v+\frac{b}{v}$ $ \begin{aligned} & \Rightarrow \frac{d C}{d v}=a-\frac{b}{v^2} \\ & \frac{d C}{d v}=0 \Rightarrow a-\frac{b}{v^2}=0 \\ & \Rightarrow v=\sqrt{\frac{b}{a}}=\sqrt{3600} \\ & \Rightarrow v=60 \mathrm{kmph} \end{aligned} $

Asked in: JEE Main 2013 (23 Apr Online)

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