
The correct truth table for the following logic circuit is :

- $\begin{array}{|l|l|l|} \hline A & B & Y \\ \hline 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 0 \\ 1 & 1 & 1 \\ \hline \end{array}$
- $\begin{array}{|l|l|l|} \hline A & B & Y \\ \hline 0 & 0 & 0 \\ 0 & 1 & 1 \\ 1 & 0 & 0 \\ 1 & 1 & 1 \\ \hline \end{array}$
- $\begin{array}{|l|l|l|} \hline A & B & Y \\ \hline 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 0 \\ 1 & 1 & 0 \\ \hline \end{array}$
- $\begin{array}{|l|l|l|} \hline A & B & Y \\ \hline 0 & 0 & 0 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \\ 1 & 1 & 1 \\ \hline \end{array}$
Asked in: JEE Main 2024 (06 Apr Shift 1)