The correct thermodynamic conditions for the spontaneous reaction at all temperatures is:

The correct thermodynamic conditions for the spontaneous reaction at all temperatures is:

$∆ H < 0$ and $∆ S = 0$
$∆ H > 0$ and $∆ S < 0$
$∆ H < 0$ and $∆ S > 0$
$∆ H < 0$ and $∆ S < 0$

Solution

∆ G = ∆ H - T ∆ S

for spontaneous reaction

Δ G < 0

Hence for Spontaneous reaction at all temperature

∆ H < 0, ∆ S > 0

Asked in: NEET 2016 (Phase 1)

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