The correct stability order of alkyl substituted alkenes is
- $\mathrm{R}_2 \mathrm{C}=\mathrm{CHR} \gt \mathrm{R}_2 \mathrm{C}=\mathrm{CH}_2 \gt \mathrm{R}_2 \mathrm{C}=\mathrm{CR}_2$
- $\mathrm{R}_2 \mathrm{C}=\mathrm{CR}_2 \gt \mathrm{R}_2 \mathrm{C}=\mathrm{CHR} \gt \mathrm{R}_2 \mathrm{C}=\mathrm{CH}_2$
- $\mathrm{R}_2 \mathrm{C}=\mathrm{CH}_2 \gt \mathrm{R}_2 \mathrm{C}=\mathrm{CR}_2 \gt \mathrm{R}_2 \mathrm{C}=\mathrm{CHR}$
- $\mathrm{R}_2 \mathrm{C}=\mathrm{CR}_2 \gt \mathrm{R}_2 \mathrm{C}=\mathrm{CH}_2 \gt \mathrm{R}_2 \mathrm{C}=\mathrm{CHR}$
Solution
Greater is the number of alkyl groups attached to the doubly bonded carbon atoms, greater is the stability of alkene.
Asked in: MHT CET 2024 (15 May Shift 2)
Practice more General Organic Chemistry questions on Aicharya