The correct shape and I - I - I bond angles respectively in I 3 - ion are:

The central iodine atom undergoes ${\mathrm{sp}}^3\mathrm{d}$ hybridization and has 3 lone pairs of electrons and 2 bond pairs of electrons.

Thus, ${\mathrm{I}}_3^{-}$ has trigonal bipyramidal geometry and linear shape .

Shape : Linear, I-I-I Bond angle $\Rightarrow 180°$