The correct relation between total magnetic field (B), magnetic intensity (H), permeability of free space…

The correct relation between total magnetic field (B), magnetic intensity (H), permeability of free space $\left(\mu_0\right)$ and susceptibility $(\chi)$ is
  1. $\frac{B}{\mathrm{H}}=\mu_0(1-\chi)$
  2. $\frac{\mathrm{B}}{\mathrm{H}}=\mu_0(1+\chi)^2$
  3. $\frac{\mathrm{B}}{\mathrm{H}}=\mu_0(1+\chi)$
  4. $\frac{\mathrm{B}}{\mathrm{H}}=\mu_0(1-\chi)^2$

Solution

The general relationship between $\mathbf{B}, \mathrm{H}$, and the material properties is given by: $B=\mu_0(1+\chi) H$
Where: - $\mathbf{B}$ is the magnetic flux density, - H is the magnetic field intensity, - $\mu_0$ is the permeability of free space, - X is the magnetic susceptibility.

Asked in: MHT CET 2024 (09 May Shift 2)

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