The correct position $(\mathrm{x})$ - time $(\mathrm{t})$ graph for a particle moving with negative…
The correct position $(\mathrm{x})$ - time $(\mathrm{t})$ graph for a particle moving with negative acceleration is
Solution
As acceleration is negative, so particle velocity will first increase, will become zero and then start increasing in opposite direction.
So, particle displacement will first increase, reaches maximum and then start decreasing. so option (a) is correct.
