The correct order of stability is

The correct order of stability is
  1. $\mathrm{CCl}_{2} < \mathrm{SiCl}_{2} < \mathrm{SnCl}_{2} < \mathrm{PbCl}_{2}$
  2. $\mathrm{CCl}_{2}>\mathrm{SiCl}_{2}>\mathrm{SnCl}_{2}>\mathrm{PbCl}_{2}$
  3. $\mathrm{SiCl}_{2}>\mathrm{CCl}_{2}>\mathrm{SnCl}_{2}>\mathrm{PbCl}_{2}$
  4. $\mathrm{SnCl}_{2}>\mathrm{CCl}_{2}>\mathrm{SiCl}_{2}>\mathrm{PbCl}_{2}$

Solution

$\mathrm{MX}_{2}$ Stability of di halides increases, down to the group due to inert pair effect ,

Asked in: JEE-TOPICTESTS-CHEMISTRY

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