The correct order of pseudohalide, polyhalide and interhalogen are
- $\mathrm{BrI}_{2}^{-}, \mathrm{OCN}^{-}, \mathrm{IF}_{5}$
- $\mathrm{IF}_{5}, \mathrm{BrI}_{2}^{-}, \mathrm{OCN}^{-}$
- $\mathrm{OCN}^{-}, \mathrm{IF}_{5}, \mathrm{Brl}_{2}^{-}$
- $\mathrm{OCN}^{-}, \mathrm{BrI}_{2}^{-}, \mathrm{IF}_{5}$
Solution
Halogen, among themselves, form complex ions which are called polyhalide ions. e.g., $\mathrm{I}_{3}^{-}, \mathrm{BrI}_{2}^{-}$ etc.
Similarly, interhalogens are the compounds of halogen in which one halogen is cation and other halogen is anion. E.g., $\mathrm{IF}_{7}, \mathrm{ICl}_{5}$, $\mathrm{BrF}_{3}, \mathrm{IF}_{5}$ etc .
Asked in: JEE-TOPICTESTS-CHEMISTRY
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