The correct order of magnetic moments (spin only values in B.M.) among is
- $\left[\mathrm{MnCl}_4\right]^{2-}>\left[\mathrm{CoCl}_4\right]^{-2}>\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{-4}$
- $\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{-4}>\left[\mathrm{CoCl}_4\right]^{2-}>\left[\mathrm{MnCl}_4\right]^{2-}$
- $\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-}>\left[\mathrm{MnCl}_4\right]^{2-}>\left[\mathrm{CoCl}_4\right]^{2-}$
- $\left[\mathrm{MnCl}_4\right]^{2^{-}}>\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-}>\left[\mathrm{CoCl}_4\right]^{2-}$ (Atomic numbers: $\mathrm{Mn}=25 ; \mathrm{Fe}=26, \mathrm{Co}=27$ )
Solution
Asked in: JEE Main 2004