The correct order of increasing acid strength of the compounds (A) $\mathrm{CH}_{3} \mathrm{CO}_{2}…
The correct order of increasing acid strength of the compounds
(A) $\mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H}$
(B) $\mathrm{MeOCH}_{2} \mathrm{CO}_{2} \mathrm{H}$
(C) $\mathrm{CF}_{3} \mathrm{CO}_{2} \mathrm{H}$
(D)
is
$D < A < B < C$
$A < D < B < C$
$B < D < A < C$
$D < A < C < B$
Solution
The correct order of increasing acid strength $(\mathrm{Me})_{2} \mathrm{CH} . \mathrm{COOH} < \mathrm{CH}_{3} \mathrm{COOH} < \mathrm{MeOCH}_{2} \mathrm{COOH}$ $ < \mathrm{CF}_{3} \mathrm{COOH}$
Electron withdrawing groups increase the acid strength and electron donating groups decrease the acid strength.
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