The correct order of energy of absorption for the following metal complexes is
$A : {[Ni {(en)}_{3}]}^{2 +}, B : {[Ni {({NH}_{3})}_{6}]}^{2 +}, C : {[Ni {(H_{2} O)}_{6}]}^{2 +}$

Question

The correct order of energy of absorption for the following metal complexes is A : Ni en 3 2 + , B : Ni NH 3 6 2 + , C : Ni H 2 O 6 2 +

Aicharya · Accepted Answer

Stronger the ligand, larger the splitting energy & higher the energy of absorption. Among the given options en is the strongest ligand due to ring formation than ammonia and than water. In all complex metal ion is same with same oxidation state.
$\underset{A}{{[Ni {(en)}_{3}]}^{+ 2}} > \underset{B}{{[Ni {({NH}_{3})}_{6}]}^{+ 2}} > \underset{C}{{[Ni {(H_{2} O)}_{6}]}^{+ 2}}$

The correct order of energy of absorption for the following metal complexes is A : Ni en 3 2 + , B : Ni NH 3…

Solution