The correct order of energies of molecular orbitals of N 2 molecule, is:

1. $\left({\mathrm{\sigma }}_{1\mathrm{s}})<\right({{\mathrm{\sigma }}^{*}}_{1\mathrm{s}})< ({\mathrm{\sigma }}_{2\mathrm{s}})< ({\mathrm{\sigma }}_{2\mathrm{s}}*)<\left({\mathrm{\pi }}_{2{\mathrm{p}}_{\mathrm{x}}})=\right({\mathrm{\pi }}_{2{\mathrm{p}}_{\mathrm{y}}})<\left({{\mathrm{\pi }}^{*}}_{2{\mathrm{p}}_{\mathrm{x}}})=\right({{\mathrm{\pi }}^{*}}_{2{\mathrm{p}}_{\mathrm{y}}})<({\mathrm{\sigma }}_{2{\mathrm{p}}_{\mathrm{z}}})<({{\mathrm{\sigma }}^{*}}_{2{\mathrm{p}}_{\mathrm{z}}})$
2. $\left({\mathrm{\sigma }}_{1\mathrm{s}})<\right({{\mathrm{\sigma }}^{*}}_{1\mathrm{s}})< ({\mathrm{\sigma }}_{2\mathrm{s}})< ({\mathrm{\sigma }}_{2\mathrm{s}}*)<\left({\mathrm{\pi }}_{2{\mathrm{p}}_{\mathrm{x}}})=\right({\mathrm{\pi }}_{2{\mathrm{p}}_{\mathrm{y}}})<\left({\mathrm{\sigma }}_{2{\mathrm{p}}_{\mathrm{z}}}\right)<\left({{\mathrm{\pi }}^{*}}_{2{\mathrm{p}}_{\mathrm{x}}})=\right({{\mathrm{\pi }}^{*}}_{2{\mathrm{p}}_{\mathrm{y}}})<\left({{\mathrm{\sigma }}^{*}}_{2{\mathrm{p}}_{\mathrm{z}}}\right)$
3. $\left({\mathrm{\sigma }}_{1\mathrm{s}})<\right({{\mathrm{\sigma }}^{*}}_{1\mathrm{s}})< ({\mathrm{\sigma }}_{2\mathrm{s}})< ({\mathrm{\sigma }}_{2\mathrm{s}}*)<\left({\mathrm{\sigma }}_{2{\mathrm{p}}_{\mathrm{z}}}\right)<\left({\mathrm{\pi }}_{2{\mathrm{p}}_{\mathrm{x}}})=\right({\mathrm{\pi }}_{2{\mathrm{p}}_{\mathrm{y}}})<\left({{\mathrm{\pi }}^{*}}_{2{\mathrm{p}}_{\mathrm{x}}})=\right({{\mathrm{\pi }}^{*}}_{2{\mathrm{p}}_{\mathrm{y}}})<\left({{\mathrm{\sigma }}^{*}}_{2{\mathrm{p}}_{\mathrm{z}}}\right)$
4. $\left({\mathrm{\sigma }}_{1\mathrm{s}})<\right({{\mathrm{\sigma }}^{*}}_{1\mathrm{s}})< ({\mathrm{\sigma }}_{2\mathrm{s}})< ({\mathrm{\sigma }}_{2\mathrm{s}}*)<\left({\mathrm{\sigma }}_{2{\mathrm{p}}_{\mathrm{z}}}\right)<({{\mathrm{\sigma }}^{*}}_{2{\mathrm{p}}_{\mathrm{z}}})<\left({\mathrm{\pi }}_{2{\mathrm{p}}_{\mathrm{x}}})=\right({\mathrm{\pi }}_{2{\mathrm{p}}_{\mathrm{y}}})<\left({{\mathrm{\pi }}^{*}}_{2{\mathrm{p}}_{\mathrm{x}}})=\right({{\mathrm{\pi }}^{*}}_{2{\mathrm{p}}_{\mathrm{y}}})$

Solution

Asked in: NEET 2023 (All India)

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